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x^2-62x+70=0
a = 1; b = -62; c = +70;
Δ = b2-4ac
Δ = -622-4·1·70
Δ = 3564
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3564}=\sqrt{324*11}=\sqrt{324}*\sqrt{11}=18\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-18\sqrt{11}}{2*1}=\frac{62-18\sqrt{11}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+18\sqrt{11}}{2*1}=\frac{62+18\sqrt{11}}{2} $
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